The pH of water 40^0C is 6.8. If the density of water 40^0C is assumed to 1, g, cm^{-3}, its degree of dissociation will be10^{-13.6}/55.5655.56/ 10^{-13.6}55.56/ 10^{-6.5}10^{-6.8}/55.56
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SOLVED: Calculate the pH of pure water at 50 degrees Celsius. Provide the answer to 2 decimal places and show your working. Water dissociates slightly according to the equation: H2O (l) ->
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calculate the PH of solution containing 0.98g H2SO4 in 100 mL of water
